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angle of 40 degrees,ground is 16m from the ground,eye level is1.8m what is the distance between both

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Mar 25th, 2015

angle of 40 degrees,ground is 16m from the ground,eye level is1.8m what is the distance between both

the vertical distance is 1.8+16*tan40 =15.23 m.  The horizontal distance is 16m, so the distance is 
sqrt(15.23^2+16^2) =  22.1 m


Mar 25th, 2015

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