two circular arcs, ab and xy share the same center, o. point a is on ox and b is on oy. what can be said about the relation of the lengths of ab and xy
Since both the arc are having center O and a & b are the points lieing on the OX and OY
therefore both the arc are having same angle at the center means Angle aob = angle xoy
we know that angle = arc=radius hence
angle aob = ab/oa or ab/ob (Since oa =ob =radius of arc)
similarly angle xoy = xy/ox or xy/oy (Since ox =oy =radius of arc)
since angles are equal there fore we can write
ab/oa = xy/ox
or , ab/xy = oa/ox = (radius of arc ab)/(radius of arc xy)
hence the ratio of the length of the arc will be corresponding to their radius ...
Is there anyway you can show me how to draw the figure if I was asked to?
Does the figure mean XY has a greater or longer arc than AB? And why does XY overlap AB? Where is the radius?
XY arc is greater than Arc AB
OA , OB ARE radius of arc AB
and OX & OY radius of arc XY
I aspect very good remark and continued work from you ... Please select me your tutor
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