Brian has a marble collection. He has twice as many red as green. He has 10 more blue marbles than red. He has total of 50 marbles.

Let G = number of green marbles

Let R = number of red marbles

Let B = number of blue marbles

then,

R = 2G and B= R+10

Also, G+R+B = 50

Now we can substitute

G + (2G) + (R+10) = 50

3G + (2G+10) = 50

5G +10 = 50

5G = 40

G = 8

Thank you.

You're welcome:)

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