##### Camping Chairs: The number of defects per batch of camping chairs inspected.

label Statistics
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Camping Chairs: The number of defects per batch of camping chairs inspected.

Defects     0       1      2      3       4      5
Batches   95    113    87    64    13     8

Mar 26th, 2015

Please put the complete question !!!

Your question is not complete I can definitly solve it if it is complete !!!

Mar 26th, 2015

(a) Use the frequency distribution to construct a probability distribution.
(b) Graph the probability distribution using a histogram and describe its shape.
(c) Find the mean, variance, and standard deviation of the probability distribution.
(d) Interpret the results in the context of the real life situation.

Mar 26th, 2015

. In this problem, the underlying r.v. is

x = the number of defects per batch of camping chairs inspected.

(a) Construct a probability distribution.

It is given that Defects 0 1 2 3 45 Batches 95 113 87 64 13 8 The sum of the second row is 380. Divide each number in the second row by 380 and relabel the rows as follows: x 012345 P (x) .250 .297 .229 .168 .034 .021

That is, if we choose at random one of the 380 batches of chairs, the probability that batch has x = 0 defects is 0.250.

(c) We calculate the mean, variance, and standard deviation. We enter the probability distribution into two lists. L1 012345 L2 .250 .297 .229 .168 .034 .021 Now, entering 1-Var Stats L1,L2, we see that μ = 1.5, σ2 x ≈ 1.54, σx ≈ 1.24 . (The value of σ2 x was obtained squaring the value of σx.)

Mar 26th, 2015

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Mar 26th, 2015
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Mar 26th, 2015
Sep 23rd, 2017
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