If 188g of Sodium reacts with excess Strontium Chloride, how many grams of Sodium product should form?

Balanced reaction equation: 2 Na + Sr Cl2 => 2 NaCl + Sr

188 g Na = 188/22.99 = 8.177 mol Na will produce the same number of moles of NaCl (the coefficients in the equation are equal)

8.177 mol NaCl = 8.177 mol * 58.44 g/mol = 478 g NaCl.

Answer: 478 g NaCl.

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