If 188g of Sodium reacts with excess Strontium Chloride, how many grams of Sodium product should form?
Balanced reaction equation: 2 Na + Sr Cl2 => 2 NaCl + Sr
188 g Na = 188/22.99 = 8.177 mol Na will produce the same number of moles of NaCl (the coefficients in the equation are equal)
8.177 mol NaCl = 8.177 mol * 58.44 g/mol = 478 g NaCl.
Answer: 478 g NaCl.
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