Time remaining:
Standard Deviation question

Statistics
Tutor: None Selected Time limit: 1 Day

A population has a mean of 78 with a standard deviation of 9.8

a.) What is the probability that one element of the population selected at random is between 72 and 91?

b.) What is the probability that a random sample of 36 from this population has a sample mean between 77 and 79?

Mar 28th, 2015

Pr (72<x<91) = pr (-6/9.8<z<13/9.8) = pr (-0.61<z<1.33) = P(Z<1.33)-P(Z<-0.61) =  0.908-0.271 = 0.637

b) std = 9.8/6 = 1.633

Pr(77<x<79) = pr ((77-78)/1.63<z<79-78/1.63) =  Pr(-0.613<z<0.613) = 0.729-0.271 = 0.459

Mar 28th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Mar 28th, 2015
...
Mar 28th, 2015
May 27th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer