Can someone show me how to attempt this?

Algebra
Tutor: None Selected Time limit: 1 Day

Mar 28th, 2015

3√(x-7) + 6 = 4

subtract 6 on both sides, we get

3√(x-7) + 6 - 6 = 4 - 6

3√(x-7) = - 2

3√(x-7) = - 2

taking cube on both sides, we get

[ 3√(x-7) ]^3 = (- 2)^3

x - 7 = - 8

now add 7 on both sides ,we get

x - 7 + 7 = - 8 + 7

x = - 1

Hence     x = - 1

Mar 28th, 2015

Thank you so much! I see now. However, if you dont mind, can you explain what happens to the radical that contains x-7 because I can't cube root it so im a little confused. Do we just get rid of it?

Mar 28th, 2015

3√(x - 7) means (x - 7)^1/3 

So now if we take cube(power of three), then the the radical will be cancelled.

{(x - 7)^1/3}^3

(x - 7)^1/3*3

(x - 7)^1 Or simply (x - 7)

Mar 28th, 2015

ahhh. oh ok. now I see. I attempted another problem and I got the problem correct! thanks! Also, how many questions am I allowed to ask you? this is my first time using this app..

Mar 28th, 2015

I don't know that how many you can ask. Thanks :)

Please best.

Mar 28th, 2015
Mar 28th, 2015
Mar 28th, 2015

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