How many moles of hydrochloric acid will be formed upon the complete reaction of 0.300moles Chlorine gas with excess water?
6 CL + 3 H2O = 5 HCL + HCLO3
if 6CL=0.300 MOLES
Therefore 5 HCL=5/6*0.300moles
=0.25moles of hydrochloric acid
0.250 moles HCL Answer
I understand how to balance the formula but home assignment stated you were wrong they did 0.300 x5molh20/3molcl2=0.500
0.300 mol Cl2 5 mol HCl...=...0.500 mol HCl
the baseline in the equation is to first balance the equation. Then you correlate the ratios obtained while balancing the equations.
chlorine reacts completely in this equation
In this case, mole ratio of Cl: hcl=6:5 therefore, the moles of chlorine would be
5/6*0.3 moles=0.25 moles
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