Time remaining:
##### Finding the moles of HCL when given 0.300 moles of Chlorine

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

How many moles of hydrochloric acid will be formed upon the complete reaction of 0.300moles Chlorine gas with excess water?

Oct 20th, 2017

chemical equation

6 CL + 3 H2O = 5 HCL + HCLO3

if 6CL=0.300 MOLES

Therefore 5 HCL=5/6*0.300moles

=0.25moles of hydrochloric acid

Mar 28th, 2015

I understand how to balance the formula but home assignment stated you were wrong they did 0.300 x5molh20/3molcl2=0.500

Mar 28th, 2015

0.300 mol Cl2 5 mol HCl...=...0.500 mol HCl

3 mol Cl2

Mar 28th, 2015

the baseline in the equation is to first balance the equation. Then you correlate the ratios obtained while balancing the equations.

chlorine reacts completely in this equation

In this case, mole ratio of Cl: hcl=6:5 therefore, the moles of chlorine would be

5/6*0.3 moles=0.25 moles

Mar 28th, 2015

...
Oct 20th, 2017
...
Oct 20th, 2017
Oct 21st, 2017
check_circle