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Mar 29th, 2015

So 7x^3-19x^2-12x+48 / (x-2) = (7x^3+5x^2+2x) + 52/(x-2)

Hence the answer is NO, (x-2) is not the factor of given polynomial


Mar 29th, 2015

small correction

So 7x^3-19x^2-12x+48 / (x-2) = (7x^2+5x+2) + 52/(x-2)

Mar 29th, 2015

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Mar 29th, 2015
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Mar 29th, 2015
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