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Find the absolute maximum and minimum, if either exits

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f(x)=x^2-8x+2

Oct 19th, 2017

x2 -8x+2

(x-4)2-16+2 = (x-4)2 -14

This function attains absolute minimum at x= 4 .

The minimum value = -14

There is no maximum.

It is infinite.


Mar 29th, 2015

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pLease see the attached workbook.

parabola_mar29.xlsx 

Mar 30th, 2015

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