how to write a quadratic equation that has interger coefficients and has as solutions the given pair of numbers -1/3 and -4.

solution :

This is the formula for finding quadratic equation when solutions or roots are given

X^{2}(sum of roots) + x(product of roots) =0 ---------------------1

-1/3 , -4 are the given roots

Sum of roots = - 1/3 - 4 =( -1- 12)/3 = - 13/3

Product of roots = - 1/3 x - 4 = 4/3

Putting these values in the above equation formula -------------1

We have :

X^{2} (- 13/3) + x( 4/3) =0

Now we have same denominators 3 so, we can simplify like this :

- 13 X^{2} + 4x = 0 x3 =0

Or 13 X^{2} – 4x =0 taking ‘ –‘ as common

thanks

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