Need help with Probability

Mathematics
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It is known that 25% of the world's population is a carrier for Genetic Trait X. Suppose 8 people are randomly selected. What is the probability that at least 2 of them are carriers of Genetic Trait X? Hint: Treat this as a Binomial Experiment.

Mar 30th, 2015

n = 8

p = 0.25

x >= 2

P(x>=2 | n=8, p =0.25) = 1-p(x<=1 | n=8, p =0.25) = 1- [8C0 (.25)0 (0.75)8+8C0 (.25)1 (0.75)7 ]

= 1- 0.100113-0.266968= 1-0.367081= 0.632919 = 0.6329

Answer : 0.6329

Mar 30th, 2015

If you need any clarification, I can help you. I want your total satisfaction and best rating for me

Mar 30th, 2015

P(x>=2) = 1-p(x<=1 | n=8, p =0.25) = 1- [8C0 (.25)0 (0.75)8+8C1 (.25)1 (0.75)7 ]

= 0.6329

Mar 30th, 2015

Please note the correction in second term of binomial

Mar 30th, 2015

See I made the correction within the 20 minutes. Please revise the rating to 5. I want the best rating

Mar 30th, 2015

Please edit the rating if you do not mind. I am more concerned with rating rather than compensation

Mar 30th, 2015

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