It is known that 25% of the world's population is a carrier for Genetic Trait X. Suppose 8 people are randomly selected. What is the probability that at least 2 of them are carriers of Genetic Trait X? Hint: Treat this as a Binomial Experiment.

n = 8

p = 0.25

x >= 2

P(x>=2 | n=8, p =0.25) = 1-p(x<=1 | n=8, p =0.25) = 1- [_{8}C_{0 }(.25)^{0} (0.75)^{8}+_{8}C_{0 }(.25)^{1} (0.75)^{7} ]

Answer : 0.6329

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P(x>=2) = 1-p(x<=1 | n=8, p =0.25) = 1- [_{8}C_{0 }(.25)^{0} (0.75)^{8}+_{8}C_{1 }(.25)^{1} (0.75)^{7} ]

Please note the correction in second term of binomial

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