Need help with Probability

label Mathematics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

It is known that 25% of the world's population is a carrier for Genetic Trait X. Suppose 8 people are randomly selected. What is the probability that at least 2 of them are carriers of Genetic Trait X? Hint: Treat this as a Binomial Experiment.

Mar 30th, 2015

n = 8

p = 0.25

x >= 2

P(x>=2 | n=8, p =0.25) = 1-p(x<=1 | n=8, p =0.25) = 1- [8C0 (.25)0 (0.75)8+8C0 (.25)1 (0.75)7 ]

= 1- 0.100113-0.266968= 1-0.367081= 0.632919 = 0.6329

Answer : 0.6329

Mar 30th, 2015

If you need any clarification, I can help you. I want your total satisfaction and best rating for me

Mar 30th, 2015

P(x>=2) = 1-p(x<=1 | n=8, p =0.25) = 1- [8C0 (.25)0 (0.75)8+8C1 (.25)1 (0.75)7 ]

= 0.6329

Mar 30th, 2015

Please note the correction in second term of binomial

Mar 30th, 2015

See I made the correction within the 20 minutes. Please revise the rating to 5. I want the best rating

Mar 30th, 2015

Please edit the rating if you do not mind. I am more concerned with rating rather than compensation

Mar 30th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Mar 30th, 2015
...
Mar 30th, 2015
Sep 20th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer