The circle below has center O , and its radius is 5ft . Given that =m∠AOB40°

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Mar 31st, 2015

The length of ADB = 2*pi*(1 - 40/360)*R = (80/9)*pi ft.

The area of the shaded region = pi*R^2*(1 - 40/360) = (200/9)*pi ft^2.

Mar 31st, 2015

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Mar 31st, 2015
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Mar 31st, 2015
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