systems of linear equations: 2b+u=98 3b+2u=168

Algebra
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systems of linear equations

2b+u=98

3b+2u=168

Mar 31st, 2015

You can solve this by substitution. First, rearrange the first equation to give you u as a function of b:

u = 98 - 2b

Next, substitute this expression in for u in the second equation:

3b + 2(98-2b) = 168

We now have an equation involving only b, so we can simplify and solve for b:

3b + 196 - 4b = 168

-b = -28

b = 28

Now, we can substitute this back into our equation u = 98-2b:

u = 98 - 2(28)

u = 42

Mar 31st, 2015

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Mar 31st, 2015
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