if a rectangle with a surface area of 200 square feet is divided into two squares, and one triangle has a surface area of 57 square feet, what is the area of the second triangle?
area of rectangle = 200 sq feet = base * heigh
Area of triangle is 57 sq feet = 1/2 base * height = 1/2 * b * 10
base = (57*2)/10 = 11.4
area of second triangle is = 1/2 base * height = 1/2 * 11.4 * 10 = 57 sq. feet which is inside the first square
Answer is 143sq". You suck arab.
you dint specify ...the triangle is inside the rectangle or not....
just subtract 200sq ft - 57 sq ft which is equalt to 143 sq ft..... its not the area of second traingle...it should the remaining area of triangle....
i think ....there is some mistake in the question....
if i am wrong ...please correct me...
and one more thing.... please mind your language ... and one advice for you... respect your elders....!!
best of luck...!!
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