Description
A large, simple pendulum is on display in the lobby of the United Nations building. If the pendulum is 20.0 m in length, what is the least amount of time it takes for the bob to swing from a position of maximum displacement to the equilibrium position of the pendulum? (Assume that the acceleration of gravity is g = 9.81 m/s2 at the UN building.)
sExplanation & Answer
Total time period of one round
T = 2 pi root ( L/g)
T = 2 x 3.14 root ( 20/9.81)
T = 8.96
For the pendulum to go from one extremum to centre of equlibrium = 1/4 T =1/4 x 8.96 = 2.24 seconds.
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