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A chemist runs a reaction at 50°C and determines its rate to be 0.00451 M/s. If she increases the

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temperature to 80°C, what will the rate of the reaction be?

4. A chemist runs a reaction at 25°C and determines that the reaction proceeds too

quickly. He decides that the reaction needs to be slowed down by a factor of 4.

What temp should he runThe RXN

Mar 31st, 2015

rate1 = 0.00451 M/s 
R = 8.314 J/molK 
T2 = 80+273.15 = 353.15K 
T1 = 50+273.15L = 323.15K 

BUT.. we're missing Ea... energy of activation... right? 

You cannot solve this without know that Ea value. I should be given somewhere in the problem statement.. and make sure the units cancel (should be in J / mol... not kilojoules / mol) 

once you find that value.. 
rate2 = 0.00451 M/s) / exp (((__ J/mol) / (8.314 J/molK)) x (1/353.15K - 1/323.15)) = ___ M/s

Similarly for another.

Mar 31st, 2015

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