The balanced reaction equation for combustion of heptane, C7H16 is given. If the reaction produced 21.5g CO2, how many grams of heptane were burned?
molar mass of CO2=44g/mol.
So n(heptane)=0.5/7=0.07 mole approximately. Molar mass of heptane is 100.21g/mol
So m(heptane)=M*n(heptane)=0.07mol*100.21g/mol=7 grams
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