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What are the steps to this equation

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The balanced reaction equation for combustion of heptane, C7H16 is given. If the reaction produced 21.5g CO2, how many grams of heptane were burned?

C7H16+11O2----> 7CO2+8H20

Oct 22nd, 2017

molar mass of CO2=44g/mol. 

n=m/M=21.5g/(44g/mol)=0.5 approximately

So n(heptane)=0.5/7=0.07 mole approximately. Molar mass of heptane is 100.21g/mol

So m(heptane)=M*n(heptane)=0.07mol*100.21g/mol=7 grams

Mar 31st, 2015

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Oct 22nd, 2017
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Oct 22nd, 2017
Oct 23rd, 2017
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