How much 0.0100 M HCl is required to titrate

Chemistry
Tutor: None Selected Time limit: 1 Day

Mar 31st, 2015

for Na2CO3, reaction ratio is 1:1

moles of Na2CO3=moles of HCl= 0.01*320/1000=0.0032moles

so volume= 0.0032*1000/0.01= 320ml

for NaHCO3, ratio is 1:1

so volume is same= 320ml

Mar 31st, 2015

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Mar 31st, 2015
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Mar 31st, 2015
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