Calculate the pH of a solution that

Chemistry
Tutor: None Selected Time limit: 1 Day

Mar 31st, 2015

benzoic acid = 6.6 x 10-5 

PH = PKa + log (A/HA)

PH = -log(6.6x10^-5) + log(.210 M / .130 M)

PH = 4.18 + .21 = 4.39

Mar 31st, 2015

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