1. pH= -log(H+) = -log(9.12x10^-4) = 3.04
2. pH=9.71 = Basic(anything above 7 is basic)
pOH= 14-pH = 14-9.71=4.28
H+ = 1.95x10^-10
a. BrO3- + H2O <==> HBrO3 + OH-
b. HF + H2O <------> H3O+ + F-
a. Kb = ([HBrO3][OH-]) / [BrO3-]
b. Kb = Kw/Ka = [H3O+][F-]/ [HF]
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