Statistics questions

Statistics
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Apr 1st, 2015

The critical value used to find a 98% confidence interval is Z = 2.33.
n1 = 1400, n2 = 1320
p1 = .5, p2 = .38
q1 = 1 - p1 = .5, q2 = 1 - p2 = .62
To begin, we must find the difference in proportions. This is 0.5 - 0.38 = 0.12.
We now use the formula 98 % CI = .12 +/- 2.33*sqrt(((p1*q1)/n1) + ((p2*q2)/n2)))
This gives us .12 +/- 2.33*sqrt(((.5*.5)/1400) + ((.38*.62)/1320)))
Simplifying, we get .12 +/- .04, so our 98% confidence interval is (0.8, 0.16).

Apr 1st, 2015

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