Statistics questions

Statistics
Tutor: None Selected Time limit: 1 Day

Apr 1st, 2015

The critical value used to find a 98% confidence interval is Z = 2.33.
n1 = 1400, n2 = 1320
p1 = .5, p2 = .38
q1 = 1 - p1 = .5, q2 = 1 - p2 = .62
To begin, we must find the difference in proportions. This is 0.5 - 0.38 = 0.12.
We now use the formula 98 % CI = .12 +/- 2.33*sqrt(((p1*q1)/n1) + ((p2*q2)/n2)))
This gives us .12 +/- 2.33*sqrt(((.5*.5)/1400) + ((.38*.62)/1320)))
Simplifying, we get .12 +/- .04, so our 98% confidence interval is (0.8, 0.16).

Apr 1st, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Apr 1st, 2015
...
Apr 1st, 2015
Dec 10th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer