pH of milk of magnesia

Chemistry
Tutor: None Selected Time limit: 1 Day

Apr 1st, 2015

Mg(OH)2 <------>Mg2+ + 2 OH¯

Ksp = [Mg2+] [OH¯]2

5.6 x 10¯12 = (x) (2x)2 = 4x3

After dividing by 4 and then taking the cube root:

x = 1.12 x 10¯4 M

This is an important point: what we have calculated is 'x' and it is NOT the [OH¯]. That value is '2x.'

[OH¯] = 2.24 x 10¯4 M

pOH = - log 2.24 x 10¯4 = 3.650

pH = 14 - 3.650 = 10.350

Apr 1st, 2015

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