First find the molarity of the salt:
1 NaOH & 1 HNO2 --> 1 NaNO2 & H2O 0.05 litres @ 0.25mol / litre HNO2 = 0.2 moles of HNO2 0.2 moles of HNO2 needs 0.2 moles of NaOH 0.2 moles of NaOH @ 1mol/litre = 0.2 litres of NaOH your NaNO2 : 0.2 mol / 0.25 litres = 0.8 Molar ----------------------------------- the (NO2)- ion from the weak acid will do a hydrolysis with water, producing a basic solution : NO2- in water --> HNO2 & OH- the K hydrolysis = K water / K acid = 1e-14 / 5.1e-4 = 1.96e-11 1.96e-11 = [HNO2] [OH-] / [NO2-] 1.96e-11 = [x] [x] / [0.8] x2 = 1.568e-11x = [OH-] = 3.98e-6 pOH = 5.4pH = 14 - pOH = 8.6your answer: = 8.6
Screen Shot 2015-04-01 at 8.30.05 PM.png
It says its wrong so can u please recheck it.
Hey fufu, sorry for late response, can you try to type 8.35 as the answer? Let me know, thanks.
thanks that helped
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?