What is the pH of the soultions?

Chemistry
Tutor: None Selected Time limit: 1 Day

Apr 2nd, 2015

After 10 ml of added base 

Moles base added = 0.138*0.005 = 0.00069 

This equals moles of acid reacted 

Moles acid before reaction = 0.025*0.11 = 0.00275 

Moles acid remaining = 0.00275 - 0.00069 

= 0.00206

Volume = 25 + 10 = 0.035L 

Concentration acid remaining = 0.0021/0.035 = 0.06M 

If x moles dissociate: 

0.06 - x = x + x 

[H+][OAc-]/[HOAc] = x*x/(0.06-x) = 1.76*10^-5 

Assume x <<< 0.06, then 0.06-x ~ 0.06 

x^2 = 0.06*1.74*10^-5 

x = [H+] = 1.02*10^-3

pH = 3.0

....Do the same steps for 20mL and 30mL

Apr 2nd, 2015

it says the answer is wrong :(

Apr 2nd, 2015

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