What is the pH of the soultions?

Chemistry
Tutor: None Selected Time limit: 1 Day

Apr 2nd, 2015

pka=4.75

now when the base is added, first a buffer solution is formed until the point the whole of the acid is used up. then the ph rises due to excess of naoh

so a)when 10ml is added,

milli moles of acid left=25*0.115-0.144*10

=1.435

milli moles of salt formed=10*0.144

=1.44

so pH=pka+log(salt/acid)

=4.75+log(1.44/1.435)

=4.7515

b)when 20 ml is added,

excess milli moles of the base=20*0.144-25*0.115

=0.005

so pH=14+ log(0.005/(20+25))

=10.0458

c)when 30 ml is added,

excess milli moles of the base=30*0.144-25*0.115

=1.445

so pH=14+ log(1.445/(30+25))

=12.42



give me good review

Apr 2nd, 2015

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