calculate the pressure at the bottom of a graduated cylinder that is half full of mercury and half full of water. assume the height of the cylinder is 0.25 m and dont forget about atmospheric pressure
Since density of mercury is greater than water it will be in the lower half of cyider and water willl be in the upper half.
Both do not mix.
Pressure exerted by water = Density x g x height = 13594 x 10 x 0.0125 = 1699.25 = 1700 approx.
Pressure exerted by mercury = Density x g x height = 1000 x 10 x 0.0125 = 125
Total Pressure = Pressure by water + Pressure by Mercury + Atmospheric Pressure = 1700 + 125 + 1 = 1826 Pascal..............Answer
determine the time required for a 50 l container to be filled with water when the speed of the incoming water is 25 cm /s and the cross sedctional area of the hose carryikng the water is 3.0cm2
Can you make it a paid question ? I will explain you well !!!!
Determine the time required for a 50 l container to be filled with water when the speed of the incoming water is 25 cm /s and the cross sedctional area of the hose carryikng the water is 3.0cm2
Volume of water flowing per second = 25 x 3 = 75 cm^3
Now, volume of water in the container = 50 litre = 50000 cm^3
Time, required = 50000/75 = 666.66 seconds
Answer. Approx 667 seconds or 11 minutes.
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