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##### probability urgent question

label Algebra
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schedule 1 Day
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probability of getting sum 7 on two dice is???

Oct 20th, 2017

There are 36 possibilities, namely

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Sum of 7 is possible if (1,6),(2,5),(3,4),(4,3),(5,2) and (6,1)

There are six possibilities favorable to the sum of 7

Hence the required probability = 6/36 =1/6

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Apr 2nd, 2015

Since there is no response from you, I hope it meets your expectation.

Just to further enlighten you, the sample space consists of 36 points mentioned in my answer. Favorable event has 6 points. Thus the probability is 6/36=1/6.

I like to care for my students to the core. I am more concerned with rating rather than monetary compensation.

Apr 2nd, 2015

Thank you very much.

Apr 2nd, 2015

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Oct 20th, 2017
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Oct 20th, 2017
Oct 21st, 2017
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