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#12 please! help me


label Mathematics
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Nov 21st, 2017

1) v=f'(x)=-32x+12=0, x=0.375s

so the ball's maximum height is -16*(0.375)^2+12*0.375+3=5.25m

2) -16x^2+12x+3=4, x=0.83s, so one time the ball was above 4 feet.

3) -16x^2+12x+3=0, x=0.95s 

Let me know what do you think. 

Apr 2nd, 2015

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Apr 2nd, 2015

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