The neutralization of H2SO4(aq), using NaOH(aq), is represented the following equation: 2NaOH(aq) + H2SO4(aq) --> Na2SO4(aq) + 2H2O(l) If 25.50 mL of 0.350 M NaOH(aq) is neutralized by 17.74 mL of H2SO4(aq),what must be the molarity of the H2SO4 use
Number of moles of NaOH= O.02550L*0.350 M=0.00893 moles
The stoichimetry of this acid-base reaction is 1:2. So moles of acid reacted = 0.004465 moles
Molarity of H2SO4= 0.004465 moles /0.01774L=0.2517 M
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