graph quadratic and convert to standard form f(x) = -3 (x-4)^2 + 4
f(x)=-3(x^2-8x+16)+4=-3x^2+24x-48+4=-3x^2+24x-44 (standard form is y=ax^2+bx+c)
This graph faces adorn because a is smaller than zero.
Find points on the graph, like (0,-44), (5.15,0), (2.85,0), etc......
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