construct a 95 confidence interval for the difference p1 - p2 in each of them

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vprzna

Mathematics

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a. n1=400 p1=.65 n2=400 p2=.58

b. n1=180 p1=.31 n2=250 p2=.25

c. n1=100 p1=.46 n2=120 p2=.61

someone please help and explain to me how this works!!! Much appreciated

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Explanation & Answer

95 % conidence interval :

95% Tabular value =1.96

p1-p2 - 1.96 *sqrt (p1*(1-p1)/n1+p2*(1-p2)/n2)

p1-p2 + 1.96 *sqrt (p1*(1-p1)/n1+p2*(1-p2)/n2)

n1 400 180 100
n2 400 250 120
p1 0.65 0.31 0.46
p2 0.58 0.25 0.61
SE 0.034318 0.044027 0.066832
p1-p2 0.07 0.06 -0.15
Tabular value 1.96 1.96 1.96
Lower Limit 0.003 -0.026 -0.281
Upper Limit 0.137 0.146 -0.019


Anonymous
Excellent resource! Really helped me get the gist of things.

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