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Find the equation of the tangent

Calculus
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Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter.

x= t-t^-1

y = t + t^2

t=1

Apr 3rd, 2015

dx/dt = 1-1/t^2

dy/dt = 1+2t

dy/dx = (1+2t)/( 1-1/t^2)

At t=1 dy/dx = infinite

Hence the tangent is parallel to y axis

at t=1 y=2

Hence the tangent equation is y=2

Apr 3rd, 2015

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Apr 3rd, 2015
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Apr 3rd, 2015
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