If $6000 is invested in an account for which interest is compounded continuously

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

 find the amount of the investment at the end of 13 years for the following interest rates. (Round your answers to the nearest cent.)

(a)    2%
 

(b)    3%
 

(c)    4.5%
 

(d)    8%
Apr 4th, 2015

a) $6,000*e^(.02*13)=$7,781.58

b) $6,000*e^(.03*13)=$8,861.88

c) $6,000*e^(.045*13)=$10,769.95

d) $6,000*e^(.08*13)=$16,975.30

Apr 4th, 2015

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Apr 4th, 2015
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