FIND graph that is a polynomial in sin(t)

Calculus
Tutor: None Selected Time limit: 1 Day

FIND sin(t) graph it is a polynomial in sin(t), so there is a polynomial such that:

f(t)=g(sin(t))?

      it has horizontal tangent lines at sin(t) = 1/3 or sin t = 1 or sin t = -1

the graph passes through (0,1) and(pi/2 , 4)

interval [-pi,pi]

FIND THE FINCTION f(t)

(using these clues and derivatives)

Apr 4th, 2015

f(t) = 1 - 6 sin t + 9 sin^2 t    equals to g(sin t), where g(x) = (1 - 3x)^2

Check: f(0) = 1; f(pi/2) = 1 - 6 + 9 = 4

f '(t) = - 6 cos t + 18 sin t cost = 18 cos t (sin t - 1/3)

The tangent to the graph is horizontal when the derivative is 0, that is, if sin t = 1/3 or if cos t = 0 (note that if 

sin t = +/- 1, then cos t = 0 by the Pythagorean identity: sin^2 t + cos^2 t = 1).

 

Apr 4th, 2015

I am confused about the tangent line part do  I plug in the values into the derivative function?

Apr 6th, 2015

Yes, you just plug the values of sin t into the derivative.   

Apr 6th, 2015

Here is the graph of the function f(t) = 1 - 6 sin t + 9 sin^2 t. It has horizontal tangents at the points 

t = pi/2 + pi*k ,  t = sin^{-1} (1/3) + 2*pi*k and t = -sin^{-1} (1/3) + pi + 2*pi*k  (k = 0, +-1, +-2, ...).

Apr 6th, 2015
polynomial_graph.jpg
trigpolynomialgraph.jpg

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Apr 4th, 2015
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Apr 4th, 2015
Dec 7th, 2016
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