POM question e ( only need part E completing) my answers are attached

Dec 24th, 2013
Steve1995
Category:
Other
Price: $5 USD

Question description

A ROBOT UNLOADS A FINISHED COMPONENT FROM A MACHINE AND PLACES IT ON A GRAVITY CONVEYOR. THE CONVEYOR ACCELERATES FROM REST UNTIL IT REACHES THE BOTTOM OF THE CONVEYOR 4.5 SECONDS LATER. THE COMPONENT IS TRAVELLING AT A VELOCITY OF 1.35 M/S WHEN IT REACHES THE BOTTOM OF THE CONVEYOR WHERE , IT IS THEN STOPPED BY HITTING A BUFFER. THE COMPONENT SITS STATIONARY AWAITING PACKAGING.

 A) DETERMINE THE LINEAR ACCELERATION OF THE COMPONENT AS IT TRAVELS DOWN THE GRAVITY CONVEYOR (IGNORING FRICTIONAL FORCES. 

 B) THE CONVEYOR SECTION LENGTH IS LATER MODIFIED AND EXTENDED BY A FURTHER 1.5M. DETERMINE THE NEW VELOCITY OF THE COMPONENTS WHEN THEY REACH THE BUFFER. 

 C) EXPLAIN THE CAUSE OF THE COMPONENTS ACCELERATING FROM REST DOWN THE CONVEYOR. 

 D) DETERMINE THE FORCE EXERTED BY THE COMPONENT, OF MASS 4.5KG, DOWNWARD ON THE CONVEYOR AS IT SITS AT THE BUFFER. 

 E) EXPLAIN WHY THE COMPONENT DOES NOT ACCELERATE DOWN THROUGH THE CONVEYOR WHILST RESTING AT THE BUFFER.

A)

FOR THE FIRST PART, USE EQUATION VF = V0 + AT, WHERE V0 = 0, T = 4.5 S AND VF = 1.35 M/S
A = 1.35/4.5 = 0.3 M/S2

B)

KNOWING ACCELERATION AND NEW DISTANCE, YOU CAN DETERMINE THE NEW FINAL SPEED USING EQUATION:
(VF)2 = V02 + 2A*D
THE PROBLEM STATES THAT IT IS EXTENDED BY AN ADDITIONAL 1.5 M, SO YOU'LL HAVE TO FIRST DETERMINE THE INITIAL LENGTH BEFORE THE EXTENSION:
D = VF2/2A = (1.35)^2/(2*.3) = 3.0375 M
NOW YOU ADD 1.5 TO THAT DISTANCE ABOVE AND USE THE FORMULA TO DETERMINE VF:
VF = ROOT(2*.3*4.5375) = 1.65M/S

C) GRAVITY

D)

WE KNOW THAT

VELOCITY (V) = ACCELERATION (A) X TIME (T)

1.35 = A X 4.5 ---------à A=0.3 M/S2

FORCE (F) = MASS (M) *ACCELERATION (A)

  = 4.5 KG *0.3 M/S2 =1.35

E)

THE FORCE EXERTED WILL BE EQUAL TO MASS TIMES THE GRAVITY. THAT IS 4.5*9.81= 44.145 N.

THE COMPONENT DOES NOT ACCELERATE DOWN THE CONVEYOR BELT BECAUSE WHEN ENTIRE ASSEMBLY IS CONSIDERED AS A SYSTEM, IT DOES NOT AFFECT OUR SOLUTION AND AS IT DOES NOT AFFECT THE SOLUTION. THE ACCELERATION OF ALL PARTS IS SAME AND HENCE, COMPONENT MAINTAINS ITS INERTIA UNDER THE EFFECT OF GRAVITY 


Tutor Answer

(Top Tutor) Daniel C.
(997)
School: Cornell University
PREMIUM TUTOR

Studypool has helped 1,244,100 students

8 Reviews


Summary
Quality
Communication
On Time
Value
pmallory
Dec 5th, 2016
" Totally impressed with results!! :-) "
mixedballz
Nov 26th, 2016
" excellent work as always thanks for the help "
Five Star Tutor
Nov 23rd, 2016
" Outstanding Job!!!! "
kiln82
Nov 12th, 2016
" awesome work thanks "
darnay
Nov 3rd, 2016
" The best tutor out there!!!! "
likeplum4
Oct 30th, 2016
" Excellent work as usual "
kpcutie
Oct 7th, 2016
" Excellent job "
Joemoe
Sep 28th, 2016
" <3 it, thanks for saving me time. "
Ask your homework questions. Receive quality answers!

Type your question here (or upload an image)

1826 tutors are online

Brown University





1271 Tutors

California Institute of Technology




2131 Tutors

Carnegie Mellon University




982 Tutors

Columbia University





1256 Tutors

Dartmouth University





2113 Tutors

Emory University





2279 Tutors

Harvard University





599 Tutors

Massachusetts Institute of Technology



2319 Tutors

New York University





1645 Tutors

Notre Dam University





1911 Tutors

Oklahoma University





2122 Tutors

Pennsylvania State University





932 Tutors

Princeton University





1211 Tutors

Stanford University





983 Tutors

University of California





1282 Tutors

Oxford University





123 Tutors

Yale University





2325 Tutors