How large a sample would the researcher need to estimate the mean body temperature to within 0.1 degrees with 98% confidence?

Count = 58 Mean=98.896 Median=98.400 MidRange=98.600 StdDev=0.8175 Range=2.800 IntQRange= 1.050

The answer is 362 (rounded to the nearest whole number)

How did they get this answer? Please show me the steps.

sigma= 0.8175

tabular value = 2.326348 from normal tables

P(z < 2.326348) = 0.99

P( -2.326348<z < 2.326348) = 0.98

margin of error = 0.1

margin of error = tabular value * sigma /sqrt(n)

sqrt(n) = (2.326348 * 0.8175)/(0.1)=19.01789

n = 19.01789 * 19.01789 =361.6803 = 362 rounded to nearest integer.

I have used exact value here

Normally we use 2.33 instead of 2.326348

The the answer is (2.33* 0.8175/0.1)^2 = 362.8168 =363

If you have any query , please get in touch with me.

I want your complete satisfaction and best rating for me.

I hope the answer meets your expectation. If you have any query, please let me know.

There is no response from your end.

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up