what is the mass of 202.6 ml sample of hydrogen chloride gas at -12.4 c and 184 kpa
Ok, so we have to convert ml to L
202.6 ml = 0.2026 L
and convert celsius to kelvin
-12.4C = 260.75 K
Then we use PV = nRT to find out how many moles there will be
n = PV / RT
= (184)(0.2026) / (8.314)(260.75)
= 0.01725 moles
One mole of HCL = 36.4609 grams
(0.01725)(36.4609) = 0.6288 grams
Oh, one other thing I forgot. We have to convert kPa to atm
1 atm = 101.3 kPa
So, 184 kPa = 1.8164 atm
So, we have to divide the previous answer by 101.3 to get
.06288 / 101.3 = 6.2 x 10^-4 grams.
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