Ammonium nitrate decomposes (explosively) according to the following reaction.
2NH4NO3 --> 2N2 + O2 + 4H2O
Mol. wt NH4NO3 = 80.0434 g/mol
Mol. wt N2 = 28 g/mol
Mol. wt O2 = 32 g/mol
Mol. wt H2O = 18 g/mol
16.9 g of NH4NO3 = 0.211 mol
So, with decomposition of 0.211 mol of NH4NO3 , 4*0.211 moles of H2O are formed
H2O formed = 0.844 mols = 0.844 * 18 g = 15.201 gms
Sorry my bad.....
Answer is 2*0.211 = 0.422moles = 7.6 gms...
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