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2NH4NO3 " src="http://loncapa.net/res/sfu/batchelo/Gallery/rarrow.gif" align="middle" style="font-size: 13px; font-style: normal; font-variant: normal; font-family: Verdana, Arial, Helvetica, sans-serif; color: rgb(0, 0, 0);"> 2N2 + O2 + 4H2O

What mass of N2 can be formed from the decomposition of 16.9 g of NH4NO3?

What mass of O2 can be formed from the decomposition of 16.9 g of NH4NO3?

Apr 5th, 2015

Molar mass of NH4NO3 = 2*14.008 + 4*1.008 + 3*15.999 = 80.043 g/mol.

The number of moles of NH4NO3 = 16.9 g / 80.043 g/mol = 0.211 mol.

From the equation: 2NH4NO3 -> 2N2 + O2 + 4H2O it follows that there will be formed

0.211 mol N2 (1:1 coefficient ratio) = 0.211 mol * 28.016 g/mol = 5.91 g N2.

0.106 mol O2 (1:2 ratio) = 0.106 mol * 32.00 g/mol = 3.39 g O2.

Apr 5th, 2015

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Apr 5th, 2015
Sep 26th, 2017
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