can some one please help me please fast fast

label Chemistry
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2NaCl + 2H2O → 2NaOH + H2 + Cl2

2Fe + 3Cl2 → 2FeCl3

Assuming that all the chlorine generated in the first step is consumed in the second step, what mass of NaCl is needed in the first step to produce 39.2 g of FeCl3 in the second step?

A solution is made by dissolving 5.37 g of MgCO3 into enough water to make 575 mL of solution. What is the molarity of the solution?

Apr 5th, 2015

39.2 g FeCl3 = 0.242 mole.  This reacts with 0.363 mole Cl2, which reacts with 0.726 mole NaCl.

So 42.4 g of NaCl is needed. 


5.37 g Mg CO3 = 0.064 mole

So 0.064 mole is dissolved in 0.575 L

Therefore molarity = 0.064/ 0.575 = 0.11 molarity solution

Apr 5th, 2015

I have answered your questions as required.

Apr 5th, 2015

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Apr 5th, 2015
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