Calculate the mass of solute in the following NaNO3 solution: 1.52×10-2 L of a 2.41×10-2-M solution.
Calculate the volume of 1.08×10-3-M H3PO4 solution needed to provide 2.00×10-2 g of H3PO4.
tell wheather is chemical change or physical
An ice cube melts.
2.41*10^-2 M * 1.52*10^-2 L = 3.6632*10^-4 mol
22.99 g/mol + 14 g/mol + 16*3 g/mol = 84.99 g/mol
84.99 g/mol * 3.6632*10^-4 mol = 3.11*10^-2 g
1.008*3 g/mol + 30.974 g/mol + 16*4 g/mol = 97.998 g/mol
1.08*10^-3 M * V = 2*10^-2 g/(97.998 g/mol)
V = (2.04*10^-4 mol)/(1.08*10^-3 M) = 1.89*10^-1 L
An ice cube melts: chemical
An aerosol is dispensed from a pressurized can: physical
Gasoline is burned in your car engine: chemical
A coffee cup breaks as it hits the floor: physical
A well shaken can of warm soda is opened: chemical
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