label Chemistry
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Calculate the mass of solute in the following NaNO3 solution: 1.52×10-2 L of a 2.41×10-2-M solution.

Calculate the volume of 1.08×10-3-M H3PO4 solution needed to provide 2.00×10-2 g of H3PO4.

tell wheather is chemical change or physical

An ice cube melts.

An aerosol is dispensed from a pressurized can.
Gasoline is burned in your car engine.
A coffee cup breaks as it hits the floor.
A well shaken can of warm soda is opened
Apr 5th, 2015

2.41*10^-2 M * 1.52*10^-2 L = 3.6632*10^-4 mol

For NaNO3:

22.99 g/mol + 14 g/mol + 16*3 g/mol = 84.99 g/mol

84.99 g/mol * 3.6632*10^-4 mol = 3.11*10^-2 g

For H3PO4:

1.008*3 g/mol + 30.974 g/mol + 16*4 g/mol = 97.998 g/mol

1.08*10^-3 M * V = 2*10^-2 g/(97.998 g/mol)

V = (2.04*10^-4 mol)/(1.08*10^-3 M) = 1.89*10^-1 L

An ice cube melts: chemical

An aerosol is dispensed from a pressurized can: physical

Gasoline is burned in your car engine: chemical

A coffee cup breaks as it hits the floor: physical

A well shaken can of warm soda is opened: chemical

Apr 5th, 2015

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Apr 5th, 2015
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Apr 5th, 2015
Oct 21st, 2017
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