Mass of lawnmower=75 kg
Angle of handle to horizontal: 37 degrees
Force along handle without friction: 93.91 newtons
Horizontal force component: Fcos37
Vertical Force Component: Fsin37
Acceleration: 1 m/s^2
F cos 37 - uk (mg+mgsin37) = ma
F = 75+0.128(75*9.8+75*9.8*0.6)
Could you tell me why it's mgsin37, and not 93.91sin37?
maybe I understand the question wrong, I thought we are supposed to find the force. with friction, I remember its has friction of 0.128, but now can;t see it anywhere in the problem
Isn't the formula something like this: Horizontal force=Force on handle minus the force of friction, where the force of friction is the coefficient times the sum of the vertical component of the force and mg?
yes the sum is mg sin37 + mg
So replacing F with mg in Fsin37 is appropriate in this context? Because I thought F was the force on the handle.
If F is given, then what we are suppose to find in the problem
So since the sum of those two is the normal force, we use mg?
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