##### General Chemistry 1 Help

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Consider two styrofoam coffee cups. If cup 1 has 128.0mL of ager at 88.0 celsius and cup 2 has 59.6mL of water at 18.5 celsius what is the final temperature in celsius when the contents of cup 1 are poured into cup 2? Ignore the heat capacity of the cup. Assume that the density of the water is 1.00g/mL.

Apr 5th, 2015

You mention 128.0 mL of 'ager'. I am not sure if this word even exist, so I assume you misspelled the word 'water'. In case it is some other substance, then you can solve it by the example below.

Q = mass x specific heat x delta T

128 mL x 1 g/mL = 128 g
59.6 mL x 1 g/mL = 59.6 g

specific heat of water = 4.18

128 x 4.18 ( T - 88) + 59.6 x 4.18 ( T - 18.5)=0

divide by 4.18 ( specific heat of water)

128 ( T - 88 ) + 59.6 ( T - 18.5)=0

128 T - 11264 + 59.6 T - 1102.6 = 0

187.6 T = 12366.6

T = 65.9 °C

Apr 6th, 2015

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