What would the force be if he were pulling the lawnmower instead of pushing?

label Physics
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-Assuming no friction for this problem

Pushing force upon handle=93.91 newtons

-Handle has angle of 37 degrees to the horizontal

Mass of lawnmower=75 kg

Acceleration= 1 m/s^2

Horizontal force component=93.91cos(37)

Apr 6th, 2015

for pushing we have 

ma = 75 = 93.91*cos37 

it is consistent, 

for pulling we still  have 

ma = 75 = F*cos37 

the force is s till be 93.91 N, that is becasue there is no friction, pulling of push will have the same effect. 

Apr 6th, 2015

Thank you! And with friction, would it change since the vertical component is pointing upward instead of downward?

Apr 6th, 2015

yes, it will 

Apr 6th, 2015

Thanks.

Apr 6th, 2015

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Apr 6th, 2015
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Apr 6th, 2015
Oct 18th, 2017
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