-Assuming no friction for this problem
Pushing force upon handle=93.91 newtons
-Handle has angle of 37 degrees to the horizontal
Mass of lawnmower=75 kg
Acceleration= 1 m/s^2
Horizontal force component=93.91cos(37)
for pushing we have
ma = 75 = 93.91*cos37
it is consistent,
for pulling we still have
ma = 75 = F*cos37
Thank you! And with friction, would it change since the vertical component is pointing upward instead of downward?
yes, it will
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