if a,b and c are integers such that a divides b and b divides c, then a divides (b squared + c squared).
Since a divides b and b divides c, we can write,
b/a = k
c / b = p
To prove: a divides ( b^2 + c^2 )
b^2 + c^2 / a
Clearly first term will be easily divisible by a ( b /a ) b = k . b will be the resultant
c ^2 = ( p b ) ^2 = p^2 . b ^2 which when divided by a will give = p^2 . b ^2 / a = p ^2 . kb
Hence both the terms are divisible by a.
That was not how i learned to do divisibility. This is for test corrections.
You need more explanation on it...
If you can send me your solution, I can definitely explain you.
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