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What are the domain restrictions

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q^2+7q-8/q^2-3q-4?

A: q ≠ -1 and q ≠ 8

B:  q ≠ 1 and q ≠ -8

C: q ≠ -1 and q ≠ 4

D: q ≠ 1 and q ≠ -4

Apr 6th, 2015

q^2+7q-8/q^2-3q-4  to find the domain restriction you should focus on where the equation can not exist. in this case the equation can not exist when the denominator or bottom portion of the fraction eqauls 0 as you can not divide by 0

the denominator is q^2-3q-4 and we should solve for when it is equal to 0

so we have q^2-3q-4 = 0

this can be reduced to (q +4)(q-1)=0

giving us q = 1and q = -4

therefrore there are domain restrictions at these two points

this gives us D as the answer

Apr 6th, 2015

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Apr 6th, 2015
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Apr 6th, 2015
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