130 = 10*log(I/I0) = 10*[log(I) + 12] 13 = log(I) + 12 log(I) = 1, I = 10 W/m² covering an area is hemispherical so of 2*π*(1.3^2), so the total power is 10*2*π*(1.3^2) W. 106.2 W

85 dB = 10*[log(I) + 12] log(I) = -3.5I = 10^-3.5 W/m² The distance is such that the area covered by 106.2 W yields 10^-3.5 W/m²: 106.2/(2*π*r²) = 10^-3.5

r^2= 53449.62

r=231 m

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