if 375 J of heat are absorbed by the system, and it has 425 cal of work done by it, compute the change in the internal energy, and interpret the sign of your result
Change of internal energy equals heat transferred to plus work done on the gas: ∆U = Q + W = 375J -1778.2J = -1403.2J
Let me know if there is any problem
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?