Find the missing ∆H(rxn)

Chemistry
Tutor: None Selected Time limit: 1 Day

If      P4(s) + 3 O2(g) ----> P4O6(s)            ∆H(rxn) = -1640.1 kJ/mole 

and  P4(s) + 5 O2(g)----> P4O10(s)           ∆H(rxn) = -2940.1 kJ/mole

then P4O6(s) + 2 O2(g) ----> P4O10(s)     ∆H(rxn) = ?

Apr 7th, 2015

∆H(rxn) =-2940.1kJ/mole-(-1640.1kJ/mole)=-1300kJ/mole

Apr 7th, 2015

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Apr 7th, 2015
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Apr 7th, 2015
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